Carbon and its Compounds | Class 10 | Activity 4.9 with Solution

Carbon and its Compounds | Activities in Text Book with Solution

Activity 4.9

Set up the apparatus as shown in Chapter 2, Activity 2.5.

Take a spatula full of sodium carbonate in a test tube and add 2 mL of dilute ethanoic acid.

What do you observe?

✅ Answer: Following reaction occurs:

2CH₃COOH + Na₂CO₃ → 2CH₃COONa + CO₂ + H₂O

                   (Sodium acetate)

Pass the gas produced through freshly prepared lime-water. What do you observe?

✅ Answer: Lime-water turns milky. It means that the gas is CO₂.

Can the gas produced by the reaction between ethanoic acid and sodium carbonate be identified by this test?

✅ Answer: Yes. The gas is CO₂.

Repeat this Activity with sodium hydrogen carbonate instead of sodium carbonate.

✅ Answer: Reaction with sodium hydrogen carbonate:

CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂

• Activity 4.1
• Activity 4.2
• Activity 4.3
• Activity 4.4
• Activity 4.5
• Activity 4.6
• Activity 4.7
• Activity 4.8
• Activity 4.9
• Activity 4.10
• Activity 4.11
• Activity 4.12

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